annotate bk/bk3.org @ 8:4dfeaf1a70c0

typos, gender reassignment
author Dylan Holmes <ocsenave@gmail.com>
date Thu, 27 Oct 2011 23:02:59 -0500
parents 44d3dc936f6a
children
rev   line source
rlm@0 1 #+TITLE: Bugs in quantum mechanics
rlm@0 2 #+AUTHOR: Dylan Holmes
rlm@0 3 #+SETUPFILE: ../../aurellem/org/setup.org
rlm@0 4 #+INCLUDE: ../../aurellem/org/level-0.org
rlm@0 5
rlm@0 6 #Bugs in Quantum Mechanics
rlm@0 7 #Bugs in the Quantum-Mechanical Momentum Operator
rlm@0 8
rlm@0 9
rlm@0 10 I studied quantum mechanics the same way I study most subjects\mdash{}
rlm@0 11 by collecting (and squashing) bugs in my understanding. One of these
rlm@0 12 bugs persisted throughout two semesters of
rlm@0 13 quantum mechanics coursework until I finally found
rlm@0 14 the paper
rlm@0 15 [[http://arxiv.org/abs/quant-ph/0103153][/Self-adjoint extensions of operators and the teaching of quantum
rlm@0 16 mechanics/]], which helped me stamp out the bug entirely. I decided to
rlm@0 17 write an article about the problem and its solution for a number of reasons:
rlm@0 18
rlm@0 19 - Although the paper was not unreasonably dense, it was written for
rlm@0 20 teachers. I wanted to write an article for students.
rlm@0 21 - I wanted to popularize the problem and its solution because other
rlm@0 22 explanations are currently too hard to find. (Even Shankar's
rlm@0 23 excellent [[http://books.google.com/books/about/Principles_of_quantum_mechanics.html?id=2zypV5EbKuIC][textbook]] doesn't mention it.)
rlm@0 24 - I wanted to check that the bug was indeed entirely
rlm@0 25 eradicated. Attempting an explanation is my way of making
rlm@0 26 sure.
rlm@0 27
rlm@0 28 * COMMENT
rlm@0 29 I recommend the
rlm@0 30 paper not only for students who are learning
rlm@0 31 quantum mechanics, but especially for teachers interested in debugging
rlm@0 32 them.
rlm@0 33
rlm@0 34 * COMMENT
rlm@0 35 On my first exam in quantum mechanics, my professor asked us to
rlm@0 36 describe how certain measurements would affect a particle in a
rlm@0 37 box. Many of these measurement questions required routine application
rlm@0 38 of skills we had recently learned\mdash{}first, you recall (or
rlm@0 39 calculate) the eigenstates of the quantity
rlm@0 40 to be measured; second, you write the given state as a linear
rlm@0 41 sum of these eigenstates\mdash{} the coefficients on each term give
rlm@0 42 the probability amplitude.
rlm@0 43
rlm@0 44
rlm@0 45 * What I thought I knew
rlm@0 46
rlm@0 47 The following is a list of things I thought were true of quantum
rlm@0 48 mechanics; the catch is that the list contradicts itself.
rlm@0 49
rlm@0 50 - For any hermitian operator: Eigenstates with different eigenvalues are orthogonal.
rlm@0 51 - For any hermitian operator: Any physically allowed state can be
rlm@0 52 written as a linear sum of eigenstates of the operator.
rlm@0 53 - The momentum operator and energy operator are hermitian, because
rlm@0 54 momentum and energy are measureable quantities.
rlm@0 55 - In vacuum,
rlm@0 56 - the momentum operator has an eigenstate
rlm@0 57 \(p(x)=\exp{(ipx/\hbar)}\) for each value of $p$.
rlm@0 58 - the energy operator has an eigenstate \(|E\rangle =
rlm@0 59 \alpha|p\rangle + \beta|-p\rangle\) for any \(\alpha,\beta\) and
rlm@0 60 the particular choice of momentum $p=\sqrt{2mE}$.
rlm@0 61 - In the infinitely deep potential well,
rlm@0 62 - the momentum operator has eigenstates with the same form $p(x) =
rlm@0 63 \exp{(ipx/\hbar)}$, but because of the boundary conditions on the
rlm@0 64 well, the following modifications are required.
rlm@0 65 - The wavefunction must be zero everywhere outside the well. That
rlm@0 66 is, \(p(x) = \begin{cases}\exp{(ipx/\hbar)},& 0\lt{}x\lt{}a;
rlm@0 67 \\0, & \text{for }x<0\text{ or }x>a \\ \end{cases}\)
rlm@0 68 #0,&\text{for }x\lt{}0\text{ or }x\gt{}a\end{cases}\)
rlm@0 69 - no longer has an eigenstate for each value
rlm@0 70 of $p$. Instead, only values of $p$ that are integer multiples of
rlm@0 71 $\pi a/\hbar$ are physically realistic.
rlm@0 72
rlm@0 73
rlm@0 74
rlm@0 75 * COMMENT:
rlm@0 76
rlm@0 77 ** Eigenstates with different eigenvalues are orthogonal
rlm@0 78
rlm@0 79 #+begin_quote
rlm@0 80 *Theorem:* Eigenstates with different eigenvalues are orthogonal.
rlm@0 81 #+end_quote
rlm@0 82
rlm@0 83 ** COMMENT :
rlm@0 84 I can prove this: if $\Lambda$ is any linear operator, suppose $|a\rangle$
rlm@0 85 and $|b\rangle$ are eigenstates of $\Lambda$. This means that
rlm@0 86
rlm@0 87
rlm@0 88 \(
rlm@0 89 \begin{eqnarray}
rlm@0 90 \Lambda |a\rangle&=& a|a\rangle,\\
rlm@0 91 \Lambda|b\rangle&=& b|b\rangle.\\
rlm@0 92 \end{eqnarray}
rlm@0 93 \)
rlm@0 94
rlm@0 95 If we take the difference of these eigenstates, we find that
rlm@0 96
rlm@0 97 \(
rlm@0 98 \begin{eqnarray}
rlm@0 99 \Lambda\;\left(|a\rangle-|b\rangle\right) &=& \Lambda |a\rangle - \Lambda |b\rangle
rlm@0 100 \qquad \text{(because $\Lambda$ is linear.)}\\
rlm@0 101 &=& a|a\rangle - b|b\rangle\qquad\text{(because $|a\rangle$ and
rlm@0 102 $|b\rangle$ are eigenstates of $\Lambda$)}
rlm@0 103 \end{eqnarray}\)
rlm@0 104
rlm@0 105
rlm@0 106 which means that $a\neq b$.
rlm@0 107
rlm@0 108 ** Eigenvectors of hermitian operators span the space of solutions
rlm@0 109
rlm@0 110 #+begin_quote
rlm@0 111 *Theorem:* If $\Omega$ is a hermitian operator, then every physically
rlm@0 112 allowed state can be written as a linear sum of eigenstates of
rlm@0 113 $\Omega$.
rlm@0 114 #+end_quote
rlm@0 115
rlm@0 116
rlm@0 117
rlm@0 118 ** Momentum and energy are hermitian operators
rlm@0 119 This ought to be true because hermitian operators correspond to
rlm@0 120 observable quantities. Since we expect momentum and energy to be
rlm@0 121 measureable quantities, we expect that there are hermitian operators
rlm@0 122 to represent them.
rlm@0 123
rlm@0 124
rlm@0 125 ** Momentum and energy eigenstates in vacuum
rlm@0 126 An eigenstate of the momentum operator $P$ would be a state
rlm@0 127 \(|p\rangle\) such that \(P|p\rangle=p|p\rangle\).
rlm@0 128
rlm@0 129 ** Momentum and energy eigenstates in the infinitely deep well
rlm@0 130
rlm@0 131
rlm@0 132
rlm@0 133 * Can you measure momentum in the infinite square well?
rlm@0 134
rlm@0 135
rlm@0 136
rlm@0 137 ** COMMENT Momentum eigenstates
rlm@0 138
rlm@0 139 In free space, the Hamiltonian is \(H=\frac{1}{2m}P^2\) and the
rlm@0 140 momentum operator $P$ has eigenstates \(p(x) = \exp{(-ipx/\hbar)}\).
rlm@0 141
rlm@0 142 In the infinitely deep potential well, the Hamiltonian is the same but
rlm@0 143 there is a new condition in order for states to qualify as physically
rlm@0 144 allowed: the states must not exist anywhere outside of well, as it
rlm@0 145 takes an infinite amount of energy to do so.
rlm@0 146
rlm@0 147 Notice that the momentum eigenstates defined above do /not/ satisfy
rlm@0 148 this condition.
rlm@0 149
rlm@0 150
rlm@0 151
rlm@0 152 * COMMENT
rlm@0 153 For each physical system, there is a Schr\ouml{}dinger equation that
rlm@0 154 describes how a particle's state $|\psi\rangle$ will change over
rlm@0 155 time.
rlm@0 156
rlm@0 157 \(\begin{eqnarray}
rlm@0 158 i\hbar \frac{\partial}{\partial t}|\psi\rangle &=&
rlm@0 159 H |\psi\rangle \equiv\frac{P^2}{2m}|\psi\rangle+V|\psi\rangle \end{eqnarray}\)
rlm@0 160
rlm@0 161 This is a differential equation; each solution to the
rlm@0 162 Schr\ouml{}dinger equation is a state that is physically allowed for
rlm@0 163 our particle. Here, physically allowed states are
rlm@0 164 those that change in physically allowed ways. However, like any differential
rlm@0 165 equation, the Schr\ouml{}dinger equation can be accompanied by
rlm@0 166 /boundary conditions/\mdash{}conditions that further restrict which
rlm@0 167 states qualify as physically allowed.
rlm@0 168
rlm@0 169
rlm@0 170
rlm@0 171
rlm@0 172 ** Eigenstates of momentum
rlm@0 173
rlm@0 174
rlm@0 175
rlm@0 176
rlm@0 177 #In the infinitely deep well potential $V(x)=0$, the Schr\ouml{}dinger
rlm@0 178
rlm@0 179 #\(i\hbar\frac{\partial}{\partial t}|\psi\rangle = H|\psi\rangle\)
rlm@0 180
rlm@0 181
rlm@0 182
rlm@0 183
rlm@0 184
rlm@0 185
rlm@0 186
rlm@0 187 * COMMENT
rlm@0 188
rlm@0 189 #* The infinite square well potential
rlm@0 190
rlm@0 191 A particle exists in a potential that is
rlm@0 192 infinite everywhere except for a region of length \(a\), where the potential is zero. This means that the
rlm@0 193 particle exists in a potential[fn:coords][fn:infinity]
rlm@0 194
rlm@0 195
rlm@0 196 \(V(x)=\begin{cases}0,&\text{for }\;0< x< a;\\\infty,&\text{for
rlm@0 197 }\;x<0\text{ or }x>a.\end{cases}\)
rlm@0 198
rlm@0 199 The Schr\ouml{}dinger equation describes how the particle's state
rlm@0 200 \(|\psi\rangle\) will change over time in this system.
rlm@0 201
rlm@0 202 \(\begin{eqnarray}
rlm@0 203 i\hbar \frac{\partial}{\partial t}|\psi\rangle &=&
rlm@0 204 H |\psi\rangle \equiv\frac{P^2}{2m}|\psi\rangle+V|\psi\rangle \end{eqnarray}\)
rlm@0 205
rlm@0 206 This is a differential equation; each solution to the
rlm@0 207 Schr\ouml{}dinger equation is a state that is physically allowed for
rlm@0 208 our particle. Here, physically allowed states are
rlm@0 209 those that change in physically allowed ways. However, like any differential
rlm@0 210 equation, the Schr\ouml{}dinger equation can be accompanied by
rlm@0 211 /boundary conditions/\mdash{}conditions that further restrict which
rlm@0 212 states qualify as physically allowed.
rlm@0 213
rlm@0 214
rlm@0 215 Whenever possible, physicists impose these boundary conditions:
rlm@0 216 - A physically allowed state ought to be a /smoothly-varying function of position./ This means
rlm@0 217 that if a particle in the state is likely to be /at/ a particular location,
rlm@0 218 it is also likely to be /near/ that location.
rlm@0 219
rlm@0 220 These boundary conditions imply that for the square well potential in
rlm@0 221 this problem,
rlm@0 222
rlm@0 223 - Physically allowed states must be totally confined to the well,
rlm@0 224 because it takes an infinite amount of energy to exist anywhere
rlm@0 225 outside of the well (and physically allowed states ought to have
rlm@0 226 only finite energy).
rlm@0 227 - Physically allowed states must be increasingly unlikely to find very
rlm@0 228 close to the walls of the well. This is because of two conditions: the above
rlm@0 229 condition says that the particle is /impossible/ to find
rlm@0 230 outside of the well, and the smoothly-varying condition says
rlm@0 231 that if a particle is impossible to find at a particular location,
rlm@0 232 it must be unlikely to be found nearby that location.
rlm@0 233
rlm@0 234 #; physically allowed states are those that change in physically
rlm@0 235 #allowed ways.
rlm@0 236
rlm@0 237
rlm@0 238 #** Boundary conditions
rlm@0 239 Because the potential is infinite everywhere except within the well,
rlm@0 240 a realistic particle must be confined to exist only within the
rlm@0 241 well\mdash{}its wavefunction must be zero everywhere beyond the walls
rlm@0 242 of the well.
rlm@0 243
rlm@0 244
rlm@0 245 [fn:coords] I chose my coordinate system so that the well extends from
rlm@0 246 \(0<x<a\). Others choose a coordinate system so that the well extends from
rlm@0 247 \(-\frac{a}{2}<x<\frac{a}{2}\). Although both coordinate systems describe the same physical
rlm@0 248 situation, they give different-looking answers.
rlm@0 249
rlm@0 250 [fn:infinity] Of course, infinite potentials are not
rlm@0 251 realistic. Instead, they are useful approximations to finite
rlm@0 252 potentials when \ldquo{}infinity\rdquo{} and \ldquo{}the actual height
rlm@0 253 of the well\rdquo{} are close enough for your own practical
rlm@0 254 purposes. Having introduced a physical impossibility into the problem
rlm@0 255 already, we don't expect to get physically realistic solutions; we
rlm@0 256 just expect to get mathematically consistent ones. The forthcoming
rlm@0 257 trouble is that we don't.